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Did you know that every number of the form "abcabc" is divisible by 77?

@maralorn I did!

Cool, isn't it ...

100000a + 10000b + 1000c + 100a + 10b + c

because of the place value of each digit. This simplifies to: 100100a + 10010b + 1001c

Now it can be factorised into: 77(1300a + 130b + 13), which means it's divisible by 77. However, it is also divisible by 1, 7, 11, 13, 77, 91, 143, and 1001, because it can be factorised by those numbers too. #maths #math

ollibaba@ollibaba@chaos.social@maralorn Reminds me of https://www.smbc-comics.com/comic/math-translations